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What mass of Cu would be produced by the cathodic reduction of Cu2+

What mass of Cu would be produced by the cathodic reduction of Cu2+  when 1.60A of current passes through a solution of CuSO4 for 1 hour. (F=96500Cmol1 , Cu=64)
  • A. 7.64g
  • B. 3.82g
  • C. 1.91g
  • D. 0.96g
Correct Answer: Option C
Explanation

M = MmIT/96500n
Where
M=mass
Mm = Molar mass = 64g/mol
I = current = 1.6A
T= Time  =1h r=3600s
N= No of Charge = +2
M = 64x×1.6×3600/96500
M=1.91g

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