2H2 + O22 → H2+O ΔH = -571kJ In the equation above, how much heat…

2H2 + O22 → H2+O ΔH = -571kJ In the equation above, how much heat…

A.
-1142 kJ
B.
-571 kJ
C.
+1142 kJ
D.
-1713 kJ

Correct Answer: Option D
Explanation
2H2 + O22 → H2+O ΔH = -571kJ
4.0g of Hydrogen burn in air to produce -571 kJ
∴ 12.0s of Hydrogen will burn in air to produce
(12 * -571)/4 = -1713kJ

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