0.05 mol dm-3 HCl is neutralized by 25 cm3 NaOH. If the volume of acid…

0.05 mol dm-3 HCl is neutralized by 25 cm3 NaOH. If the volume of acid…

A.
0.016 mol dm-3
B.
0.032 mol dm-3
C.
0.039 mol dm-3
D.
0.064 mol dm-3

Correct Answer: Option D
Explanation
HCl + NaOH → NaCl + H2O
CAVA = NA/NB = (0.05 * 32)/(CB * 25)
∴ CB = (0.05 * 32)/25 = 0.064 mol dm-3

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